factorize the following polynomials by splitting the middle term x2+×-2
Answers
Answered by
0
Answer:
C
(x+
3
)(x+2
3
)
We have, x
2
+3
3
x+6=x
2
+(
3
+2
3
)x+6 (∵
3
+2
3
=3
3
and (
3
)(2
3
)=6 )
=x
2
+
3
x+2
3
x+(
3
)(2
3
)
={x
2
+
3
x}+{2
3
x+(
3
)(2
3
)}
=x(x+
3
)+2
3
(x+
3
)
=(x+
3
)(x+2
3
)
∴x
2
+3
3
x+6=(x+
3
)(x+2
3
)
Answered by
0
Answer:
In order to factorize x2 + bx + c we have to find numbers p and q such that p + q = b and pq = c.
(ii) After finding p and q, we split the middle term in the quadratic as px + qx and get desired factors by grouping the terms.
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