Math, asked by mrswagootd, 1 year ago

factorize the quadric equations

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Answered by abhi569
24
c)-

x^2 + 11x -26  = 0

 x^2 +(13 -2)x - 26 = 0

x^2 + 13x - 2x - 26 = 0

x(x+13) -2(x+13) = 0

(x+13)(x-2) = 0


x =-13  OR x= 2 

d)-

x^2 + 7x -30 

x^2 + (10-3)x -30 = 0

x^2 + 10x -3x -30 = 0

x(x+10) -3(x+10) = 0

(x+10)(x-3) = 0

x= -10 OR x= 3 


g)- 

x^2 - 7x +10

 x^2 - (5+2)x +10 = 0

x^2 -5x - 2x +10 = 0

x(x-5) -2(x-5) = 0

(x-2)(x-5) = 0

x = 2 OR x = 5 


h)- 

x^2 -5x -24 

x^2 -(8-3)x -24 =0

x^2 - 8x +3x - 24 = 0

x(x-8) +3(x-8) = 0


(x-8)(x+3) = 0

x= 8 OR x = -3 


c)-

6x^2 + 17x +12 

6x^2 + (9+8)x +12 = 0

6x^2+ 9x +8x + 12 = 0

3x(2x+3) + 4(2x+3) =0

(2x+3)(3x+4) = 0

x= -3/2  OR x = -4/3

d)- 

2x^2 + 9x +10

2x^2 + (4+5)x +10 =0

2x^2 + 4x +5x + 10 =0

2x(x+2) +5(x+2) = 0

(2x+5)(x+2) = 0

x= -5/2 OR x =-2 

g)-

3x^2 -10x -8 

= 3x^2 - (12-2)x -8 =0

3x^2 - 12x + 2x - 8 =0 

3x(x-4) + 2(x-4) = 0

(x-4)(3x+2) = 0

x =4  OR  x= -2/3 


h)- 

3x^2 -11x -20 

= 3x^2 - (15-4)x - 20 =0

3x^2 -15x + 4x -20 = 0

3x(x-5) + 4(x-5) = 0

(x-5) (3x+4)= 0

x= 5 OR x = -4/3


 i hope this will help you


-by ABHAY

abhi569: thanks
mrswagootd: np
Anonymous: Awesome
abhi569: Thanks
PaZuZu: Brilliant ans.
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