Question

factorize them quickly

Answer 1

It is in the form of ( a + b )^3 = a^3 + b^3 + 3a^2b + 3ab^2

here, 8a3 + b3 +12a2b+6ab2

= [2a]^3 + [b]^3 + [3*2a^2*b] + [3*2a*b^2] ;; here 8 cube is 2 so we take 2 instead of 8 and is b itself.

=[2a + b]^3 = [2a + b]*[2a + b]*[2a + b] ;; here we have to make it (a +b)^3 form so we take the first cube numbers only here the cube numbers are 2 and b .

answer = [2a + b]*[2a + b]*[2a + b]................

Answer 2

it is helpful for you..