Factorize this:plz....plz...!!!!!!
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boy2151:
hii
Pls solve and give
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(x²)²/2²+2²/(x²)²+1²
=(x²/2+2/x²+2)²
=using identity (x+y+z)²=x²+y²+z²+2xy+2yz+2zx
=[(x²)/2)²+(2/x²)²+1²+2(x²/2)(2/x²)+2+(2/x²)(1)+2(1)(x²/2)]
=(x²/2)+2/x²+1)²
=(x²/2+2/x²+1)(x²/2+2/x²+1)
=(x²/2+2/x²+2)²
=using identity (x+y+z)²=x²+y²+z²+2xy+2yz+2zx
=[(x²)/2)²+(2/x²)²+1²+2(x²/2)(2/x²)+2+(2/x²)(1)+2(1)(x²/2)]
=(x²/2)+2/x²+1)²
=(x²/2+2/x²+1)(x²/2+2/x²+1)
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