Factorize this question.
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1
by middle term splitting
, we get
2x^2 + 6x+x+3=0
2x(x+3)+1(x+3)=0
(2x+1)(x+3)=0
2x+1=0 and x+3 =0
x= -1/2 and x=-3
, we get
2x^2 + 6x+x+3=0
2x(x+3)+1(x+3)=0
(2x+1)(x+3)=0
2x+1=0 and x+3 =0
x= -1/2 and x=-3
Answered by
1
hi..friend.., here's your answer,
2x²+7x+3= 0
2x²+6x+1x+3=0
2x(x+3)+1(x+3)=0
x=-3 or -1/2
hope it helps you.,!
2x²+7x+3= 0
2x²+6x+1x+3=0
2x(x+3)+1(x+3)=0
x=-3 or -1/2
hope it helps you.,!
Abhimanyu108:
thanks
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