Factorize using identities
4x^2+4x+1
A1111:
(2x + 1)²
Answers
Answered by
13
Answer :
( 2x + 1 )²
Step-by-step explanation :
4x² + 4x + 1
On splitting the middle term ;
4x² + 2x + 2x + 1
⇒ 2x ( 2x + 1 ) + 1 ( 2x + 1 )
⇒ ( 2x + 1 ) ( 2x + 1 )
⇒ ( 2x + 1 )²
Hence, the answer is ( 2x + 1 )²
Let's check out the answer, by applying an identities ;
( a + b )² = a² + 2ab + b²
Here,
( 2x + 1 )² = (2x)² + 2 * 2x * 1 + (1)²
( 2x + 1 )² = 4x² + 4x + 1
Hence, the answer is ( 2x + 1 )²
( 2x + 1 )²
Step-by-step explanation :
4x² + 4x + 1
On splitting the middle term ;
4x² + 2x + 2x + 1
⇒ 2x ( 2x + 1 ) + 1 ( 2x + 1 )
⇒ ( 2x + 1 ) ( 2x + 1 )
⇒ ( 2x + 1 )²
Hence, the answer is ( 2x + 1 )²
Let's check out the answer, by applying an identities ;
( a + b )² = a² + 2ab + b²
Here,
( 2x + 1 )² = (2x)² + 2 * 2x * 1 + (1)²
( 2x + 1 )² = 4x² + 4x + 1
Hence, the answer is ( 2x + 1 )²
Do ans this sis
As i am having my exams i am not able too
So plz ans her
Answered by
8
:-
=> 4x² + 4x + 1
=>4x² + 2x + 2x + 1
=> 2x ( 2x + 1 ) + 1 ( 2x + 1)
=> ( 2x + 1 ) ( 2x + 1 )
=> ( 2x + 1 )² Answer ✔
_______________________
Do ans this sis
As i am having my exams i am not able too
So plz ans her
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