Factorize (x + 1) (x + 3) (x + 4) (x + 6) - 119
Answers
Answered by
4
Step-by-step explanation:
(x + 1)(x + 2)(x + 3)(x + 4) - 15
= [(x + 1)(x + 4)] [(x + 2)(x + 3)] - 15
= [x² + 5x + 4] [x² + 5x + 6] - 15
= [(x² + 5x + 5) - 1] [(x² + 5x + 5) + 1] - 15
= [(x² + 5x + 5)² - 1²] - 15
= (x² + 5x + 5)² - 16
= (x² + 5x + 5)² - 4²
= [(x² + 5x + 5) - 4] [(x² + 5x + 5)+ 4]
= (x² + 5x + 1)(x² + 5x + 9)
Answered by
0
Answer:
(x + 1)(x + 2)(x + 3)(x + 4) - 15
= [(x + 1)(x + 4)] [(x + 2)(x + 3)] - 15
= [x² + 5x + 4] [x² + 5x + 6] - 15
= [(x² + 5x + 5) - 1] [(x² + 5x + 5) + 1] - 15
= [(x² + 5x + 5)² - 1²] - 15
= (x² + 5x + 5)² - 16
= (x² + 5x + 5)² - 4²
= [(x² + 5x + 5) - 4] [(x² + 5x + 5)+ 4]
= (x² + 5x + 1)(x² + 5x + 9)
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