Question

factorize x^2/4-y^2/4 need urgently now only for 69 pts

Answer 1

Answer:

x^2 / 4 - y^2 / 4 is equal to 1 / 4 × ( x + y )( x - y ).

Step-by-step explanation:

= > $\dfrac{x^2}{4} - \dfrac{y^2}{4}$

= > $\dfrac{( x^2 - y^2 )}{4}$

From the properties of factorization :

• a^2 - b^2 = ( a + b )( a - b )

On the basis of the above formula :

= > $\dfrac{( x + y )( x - y )}{4}$

= > $\dfrac{1}{4}\times ( x + y )( x - y )$

Hence x^2 / 4 - y^2 / 4 is equal to 1 / 4 × ( x + y )( x - y ).

Answer 2

$\Large{\underline{\underline{\mathfrak{Solution :-}}}}$

$\implies \sf \frac{ {x}^{2} }{4} - \frac{ {y}^{2} }{4} \\ \\ \implies \sf \frac{( {x}^{2} - {y}^{2} ) }{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \{( {a}^{2} - {b}^{2} ) = (a - b)(a + b) \} \\ \\ \implies \sf \frac{(x - y)(x + y)}{4} \\ \\ \implies \sf \frac{1}{4} (x - y)(x + y)$