factorize (x^2-7)^2-(y+3z)^2
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Answer:
( x² + y + 3z - 7 ) ( x² - y - 3z - 7)
Step-by-step explanation:
Given :
To factorize : (x² - 7)² - (y + 3z)²
Solution :
We know this identity,
a² - b² = ( a + b ) ( a - b )
Hence,
y using this identity here, by substituting a = x² - 7 , b = y + 3z,
We get,
( x² - 7 )² - ( y + 3z )² = [ ( x - 7 ) + ( y + 3z ) ] [ ( x - 7 ) - ( y + 3z )]
⇒ [ x + y + 3z - 7 ] [ x - y - 3z - 7]
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