factorize x^3 -12x(x-4) - 64
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103
x³ -12x(x -4) -64
= x³ -3.x.4 (x -4) -(4)³
we know,
(a - b)³ = a³ - b³ - 3ab(a - b)
use, this formula ,
x³ -(4)³ -3.x.4(x -4) = (x -4)³
hence, (x -4), (x -4)and (x -4) are the factors of x³ -12x(x -4) -64
= x³ -3.x.4 (x -4) -(4)³
we know,
(a - b)³ = a³ - b³ - 3ab(a - b)
use, this formula ,
x³ -(4)³ -3.x.4(x -4) = (x -4)³
hence, (x -4), (x -4)and (x -4) are the factors of x³ -12x(x -4) -64
Answered by
17
x³ -12x(x -4) -64
= x³ -3.x.4 (x -4) -(4)³
we know,
(a - b)³ = a³ - b³ - 3ab(a - b)
use, this formula ,
x³ -(4)³ -3.x.4(x -4) = (x -4)³
hence, (x -4), (x -4)and (x -4) are the factors of x³ -12x(x -4) -64
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