Question

factorize x^3+3x^2-10x+24=0 with solution

Answer 1

p (1)= (1 )3-3 (1)2-10 (1)+24 ; = 1-6 -10+24 ; 1 -16 +24 ; 25-16 =19#0; p (-1)= (-1)3-3 (-1)2 -10 (-1)+24; -1+6+10+24 =40-1=39 ;p (2 )= (2)3-3 (2)2-10 (2)+24 = 8-12-20+24; 8-32+24= -8+8=0 then using remainder theorem we find x-2 divided by x3-3x2-10c+24 then we got a 3 factorise and factorise that