Question

Factorize x^3 - 3x^2 - 10x + 24

Answer 1

Factors of x³-3x²-10x+24

Factors of x³-3x²-10x+24= (x-2)(x-4)(x+3)

Step-by-step explanation:

Let the polyomial p(x)=x³-3x²-10x+24

= x³+(-2x²-x²)+(2x-12x)+24

=(x³-2x²)+(-x²+2x)+(-12x+24)

=x²(x-2)-x(x-2)-12(x-2)

=(x-2)(x²-x-12)

=(x-2)(x²-4x+3x-12)

=(x-2)[x(x-4)+3(x-4)]

=(x-2)[(x-4)(x+3)

=(x-2)(x-4)(x+3)

Therefore,

Factors of x³-3x²-10x+24

= (x-2)(x-4)(x+3)

Answer 2

Answer:

hy dude ur answer is

Step-by-step explanation:

P (1)= (1 )3-3 (1)2-10 (1)+24 ;

= 1-6 -10+24 ;

= 1 -16 +24 ;

= 25-16

=19#0;

p (-1)= (-1)3-3

(-1)2 -10

=(-1)+24;

= -1+6+10+24

=40-1=39

for ;p (2 )= (2)3-3 (2)2-10 (2)+24

= 8-12-20+24;

=8-32+24=

=-8+8=0 then using remainder theorem we find x-2 divided by x3-3x2-10c+24 then we got a 3 factorise and factorise that