THE FILAMENT OF AN ELECTRIC LAMP WHICH DRAWS A CURRENT OF 0.25 A IS USED FOR 4HOURS. CALCULATE THE AMOUNT OF CHARGE FLOWING THROUGH THE CIRCIUT
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Explanation:
So, I=0.25 A , T= 4 hours and Q = we have to find.So Q =IXT i.e. 0.25X4 = 25/100*4= 1 coulomb of charge flowing through the circuit.
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