Question

factorize x^3-4x^2+x+6 using identity ​

Answer 1

Answer:I will edit answer in 5 minutes first make me brainlest

Step-by-step explanation:

Answer 2

Answer:

( x − 2 ) ( x − 3 ) ( x + 1 )

Step-by-step explanation:

It is usually really, really hard to factorize a cubic function. However, for this polynomial, we can factor by grouping. We try values for splitting the term  − 4 x 2 .

For example, we split it into  − 2 x 2 − 2 x 2 .

The equation becomes this:  

( x 3 − 2 x 2 )−( 2 x 2 − x − 6 ).

We can factorize each of the expressions in the parentheses:  

x 2 ( x − 2 ) − ( x − 2 ) ( 2 x + 3 ) .

There is a common factor  ( x − 2 ) .

Factoring the common factor out, we get  

( x − 2 ) ( x 2 − 2 x − 3 ) . We then factorize  x 2 − 2 x − 3 to  ( x−3 ) ( x + 1 ) .

The fully factored form is then  ( x − 2 ) ( x − 3 ) ( x + 1 ) .

hope the answer helps you