Factorize: x^4+x^2y^2+y^4
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Answered by
2
x^4 =x^2 = a
y^4=y^2 =b
using identity we can solve this problem
(a+b) ^2 =(a^2 +2ab+b^2)
2ab = 2×x^2×y^2
so
(x^2 +y^2 )^2
hope it will help u
please mark it as brainliest
y^4=y^2 =b
using identity we can solve this problem
(a+b) ^2 =(a^2 +2ab+b^2)
2ab = 2×x^2×y^2
so
(x^2 +y^2 )^2
hope it will help u
please mark it as brainliest
Muthu2004:
I can't understand
Answered by
13
HERE IS YOUR ANSWER !!
___________________
x^4+x²y²+y^4
(x²)²+x²y²+(y²)²
(x²)²+(y²)²+x²y²+x²y²-x²y² ...[x²y² is added & subtracted]
(x²)²+(y²)²+2x²y²-x²y²
(x²+y²)²-x²y² ...[a²+b²+2ab=(a+b)²]
(x²+y²)²-(xy)²
{(x²+y²)+(xy)} {(x²+y²)-(xy)} ... [here,a²-b²=(a+b)(a-b)]
(x²+y²+xy) (x²+y²-xy)
_________________
HOPE IT WILL HELP U
:-)
___________________
x^4+x²y²+y^4
(x²)²+x²y²+(y²)²
(x²)²+(y²)²+x²y²+x²y²-x²y² ...[x²y² is added & subtracted]
(x²)²+(y²)²+2x²y²-x²y²
(x²+y²)²-x²y² ...[a²+b²+2ab=(a+b)²]
(x²+y²)²-(xy)²
{(x²+y²)+(xy)} {(x²+y²)-(xy)} ... [here,a²-b²=(a+b)(a-b)]
(x²+y²+xy) (x²+y²-xy)
_________________
HOPE IT WILL HELP U
:-)
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