factorize ((x) ^6)+9((x) ^2)+8
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Your question might be x^6+8x²+9
x^6+8x²+9
Let x²=a
(x²)³+2x²+9
=a³+2a+9
=a³+a²-a²-a+9a+9
=a²(a+1)-a(a+1)+9(a+1)
=(a+1)(a²-a+9)
Put a=x²
=(x²+1)[(x²)²-x²+9
=(x²+1)(x⁴-x²+9)
Let's check now according to your question,
x^6+9x²+8=0
x²(x⁴+9)=-8
If you take any value of x in LHS,the value would be positive,but if you see RHS it is negative.
So,positive term is not equal to negative term.
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