Math, asked by MohamedShaik6767, 9 months ago

Factorize:
x(x–2)(x–4)+4x-8

Answers

Answered by nikitasingh79
7

The expression is given as : x(x – 2) (x – 4) + 4x – 8

Here , in the given expression 4 is common factor in  4x – 8  :  

= x(x – 2) (x – 4) + 4(x – 2)

Taking (x - 2) common factor :  

= (x – 2) [x (x – 4) + 4]

= (x – 2) (x² – 4x + 4)

= (x – 2) [x² – 2 (x) (2) + (2)²]

By using the identity a² - 2ab + b² = (a - b)² :  

= (x – 2) (x – 2)²

= (x – 2)³

Hence,  the factorisation of x(x – 2) (x – 4) + 4x – 8  is  (x – 2)³.

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Answered by Anonymous
1

Answer:

Step-by-step explanation:

Taking (x - 2) common factor :  

= (x – 2) [x (x – 4) + 4]

= (x – 2) (x² – 4x + 4)

= (x – 2) [x² – 2 (x) (2) + (2)²]

By using the identity a² - 2ab + b² = (a - b)² :  

= (x – 2) (x – 2)²

= (x – 2)³

Hence,  the factorisation of x(x – 2) (x – 4) + 4x – 8  is  (x – 2)³.

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