Math, asked by vineet4138, 11 months ago

factorize:x(x^3-y^3)+3xy(x-y)​

Answers

Answered by brainlystat477
0

Answer:

x(x³-y³) + 3xy(x - y)

=> x[ (x³ - y³) +3y(x - y)]

=> x [ (x - y)(x² + xy + y²) + 3y(x - y)]

=> x(x - y) [ x² + y² +xy + 3y]

=> (x)(x - y) (x² + y² + xy + 3y)

I hope this will help you

Answered by rudraaggarwal239982
0

Hi ,

x( x³ - y³ ) + 3xy( x - y )

= x( x - y )( x² + xy + y² ) + 3xy( x - y )

= ( x - y )[ x( x² + xy + y² ) + 3xy ]

= ( x - y )[ x³ + x²y + xy² + 3xy ]

I hope this helps you.

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