factorize:x(x^3-y^3)+3xy(x-y)
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Answer:
x(x³-y³) + 3xy(x - y)
=> x[ (x³ - y³) +3y(x - y)]
=> x [ (x - y)(x² + xy + y²) + 3y(x - y)]
=> x(x - y) [ x² + y² +xy + 3y]
=> (x)(x - y) (x² + y² + xy + 3y)
I hope this will help you
Answered by
0
Hi ,
x( x³ - y³ ) + 3xy( x - y )
= x( x - y )( x² + xy + y² ) + 3xy( x - y )
= ( x - y )[ x( x² + xy + y² ) + 3xy ]
= ( x - y )[ x³ + x²y + xy² + 3xy ]
I hope this helps you.
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