Question

Factorize x(x3 – y3) + 3xy(x – y)

Answer 1

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The first term has a difference of cubes:

(x3 - y3) = (x - y)(x2 + xy + y2)

We can factor the whole thing out as

x(x - y)(x2 + xy + y2) + 3xy(x - y)

The common factor of the two terms is x(x - y).

x(x - y)[(x2 + xy + y2) + 3y] =

x(x - y)(x2 + xy + y2 + 3y)

Answer 2

Step-by-step explanation:

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