factorize (x+y)^(2)-(x+y)-20
Answers
Answered by
1
We know that (a + b)^2 = a^2 + b^2 + 2ab.
Given Equation is (x + y)^2 - (x + y) - 20
= x^2 + y^2 + 2xy - (x + y) -20
= x^2 + y^2 + 2xy - x - y - 20.
Hope this helps!
Given Equation is (x + y)^2 - (x + y) - 20
= x^2 + y^2 + 2xy - (x + y) -20
= x^2 + y^2 + 2xy - x - y - 20.
Hope this helps!
Answered by
1
hiii,
(x + y)^2 - (x + y) -20
let (x - y) be d
d^2 - d - 20
=d^2 -(5 -4)d - 20
=d^2 - 5d + 4d - 20
=d(d - 5) - 4(d - 5)
=(d - 5) (d - 4)
hope helps
(x + y)^2 - (x + y) -20
let (x - y) be d
d^2 - d - 20
=d^2 -(5 -4)d - 20
=d^2 - 5d + 4d - 20
=d(d - 5) - 4(d - 5)
=(d - 5) (d - 4)
hope helps
loganathan2:
thanks a lot
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