Question

factorize : (x² - 2x)² - 23(x² - 2x) + 120​

Answer 1

Answer:

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(x^{2}-2x)^{2}-23(x^{2}-2x)+120

(x2−2x)2−23(x2−2x)+120

Simplify

1

Expand the square

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+

Answer 2

Answer:

$(x 2 −2x 2 )−23(x 2 −2x)+120 \\ Above \: terms \: can \: be \: written \: as, \\ (x 2 −2x) 2 −15(x 2 −2x)−8(x 2 −2x)+120 \\ Take \: out \: common \: in \: all \: terms \: we \: get, \\ (x 2 −2x)(x 2 −2x−15)−8(x 2 −2x−15) \\ (x 2 −2x−15) (xx 2 −2x−8)$