Question

.
Factorize x2 +2xy +y2 -4z2​

Answer 1

Step-by-step explanation:

$x ^ { 2 } +2xy+y ^ { 2 } -4z ^ { 2 }$

Rewrite x^{2}+2xy+y^{2}-4z^{2} as \left(x+y\right)^{2}-\left(2z\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$\left(x+y-2z\right)\left(x+y+2z\right)$

$\left(x+y\right)^{2}-4z^{2}$