Question

factorize: x²+4y²-5x+10y-4xy+6​

Answer 1

Answer:

x^2+4y^2+4y-4xy-2x-8

=(x)^2+(2y)^2–2×x×2y-2x+4y-8

=(x-2y)^2–2(x-2y)-8

Let (x-2y)=p

=p^2-2p-8

=(p-4).(p+2). , putting p= x-2y

=(x-2y-4).(x-2y+2). Answer.