Factorize : (x2– x )2–8 ( x2– x ) + 12
Answers
Answered by
1
Answer:
(x²-x)²-8(x²-x)+12
= (x-3)(x+2)(x-2)(x+1)
Step-by-step explanation:
(x²-x)²-8(x²-x)+12
Let x²-x = a, the expression becomes
a²-8a+12
Splitting the middle term, we get
= a²-6a-2a+12
= a(a-6)-2(a-6)
= (a-6)(a-2)
= (x²-x-6)(x²-x-2)
= (x²-3x+2x-6)(x²-2x+x-2)
= [x(x-3)+2(x-3)][x(x-2)+1(x-2)]
=(x-3)(x+2)(x-2)(x+1)
Therefore,
(x²-x)²-8(x²-x)+12
= (x-3)(x+2)(x-2)(x+1)
•••♪
Similar questions