Question

factorize x3-3x2-10x+24

Answer 1

Answer:

Factors of x³-3x²-10x+24

Factors of x³-3x²-10x+24= (x-2)(x-4)(x+3)

Step-by-step explanation:

Let the polyomial p(x)=x³-3x²-10x+24

= x³+(-2x²-x²)+(2x-12x)+24

=(x³-2x²)+(-x²+2x)+(-12x+24)

=x²(x-2)-x(x-2)-12(x-2)

=(x-2)(x²-x-12)

=(x-2)(x²-4x+3x-12)

=(x-2)[x(x-4)+3(x-4)]

=(x-2)[(x-4)(x+3)]

=(x-2)(x-4)(x+3)

Therefore,

Factors of x³-3x²-10x+24

= (x-2)(x-4)(x+3)

•••♪

Answer 2

Answer:

Factors of x³-3x²-10x+24

Factors of x³-3x²-10x+24= (x-2)(x-4)(x+3)

Step-by-step explanation:

Let the polyomial p(x)=x³-3x²-10x+24

= x³+(-2x²-x²)+(2x-12x)+24

=(x³-2x²)+(-x²+2x)+(-12x+24)

=x²(x-2)-x(x-2)-12(x-2)

=(x-2)(x²-x-12)

=(x-2)(x²-4x+3x-12)

=(x-2)[x(x-4)+3(x-4)]

=(x-2)[(x-4)(x+3)]

=(x-2)(x-4)(x+3)

Therefore,

Factors of x³-3x²-10x+24

= (x-2)(x-4)(x+3)

Hope it helps you!:D