factorize x⁴+4+3x² who give answer I marked it brainiest
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Very easy, put x=1x=1, the polynomial will evaluate to 0. This means that (x−1)(x−1) is a factor of the polynomial.
x^4–3x^2+2x4–3x^2+2
=x^4−x^3+x^3−x^2–2x2+2
=x^4−x^3+x^3−x^2–2x^2+2
=x^3(x−1)+x^2(x−1)−2(x^2–1)
=x^3(x−1)+x^2(x−1)−2(x^2–1)
=x^3(x−1)+x^2(x−1)−2(x+1)(x−1)
=x^3(x−1)+x^2(x−1)−2(x+1)(x−1)
=(x−1){x^3+x2–2(x+1)}
=(x−1){x^3+x^2–2(x+1)}
=(x−1)(x^3+x^2–2x−2)
=(x−1)(x^3+x^2–2x−2)
=(x−1){x^2(x+1)−2(x+1)}
=(x−1){x^2(x+1)−2(x+1)}
=(x−1)(x+1)(x^2−2)
=(x−1)(x+1)(x^2−2)
x^4–3x^2+2x4–3x^2+2
=x^4−x^3+x^3−x^2–2x2+2
=x^4−x^3+x^3−x^2–2x^2+2
=x^3(x−1)+x^2(x−1)−2(x^2–1)
=x^3(x−1)+x^2(x−1)−2(x^2–1)
=x^3(x−1)+x^2(x−1)−2(x+1)(x−1)
=x^3(x−1)+x^2(x−1)−2(x+1)(x−1)
=(x−1){x^3+x2–2(x+1)}
=(x−1){x^3+x^2–2(x+1)}
=(x−1)(x^3+x^2–2x−2)
=(x−1)(x^3+x^2–2x−2)
=(x−1){x^2(x+1)−2(x+1)}
=(x−1){x^2(x+1)−2(x+1)}
=(x−1)(x+1)(x^2−2)
=(x−1)(x+1)(x^2−2)
Answered by
0
Answer:
Step-by-step explanation:
x^4+4+3x^2
=
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