Question

factorize x⁴+4+3x² who give answer I marked it brainiest

Answer 1

Very easy, put x=1x=1, the polynomial will evaluate to 0. This means that (x−1)(x−1) is a factor of the polynomial.

x^4–3x^2+2x4–3x^2+2

=x^4−x^3+x^3−x^2–2x2+2
=x^4−x^3+x^3−x^2–2x^2+2

=x^3(x−1)+x^2(x−1)−2(x^2–1)
=x^3(x−1)+x^2(x−1)−2(x^2–1)

=x^3(x−1)+x^2(x−1)−2(x+1)(x−1)
=x^3(x−1)+x^2(x−1)−2(x+1)(x−1)

=(x−1){x^3+x2–2(x+1)}
=(x−1){x^3+x^2–2(x+1)}

=(x−1)(x^3+x^2–2x−2)
=(x−1)(x^3+x^2–2x−2)

=(x−1){x^2(x+1)−2(x+1)}
=(x−1){x^2(x+1)−2(x+1)}

=(x−1)(x+1)(x^2−2)
=(x−1)(x+1)(x^2−2)

Answer 2

Answer:

Step-by-step explanation:

x^4+4+3x^2

=