Question

factorize x6+8x3+27​

Answer 1

Answer:

(x² - x +3)(x∧4 +x³ - 2x² +9)

Step-by-step explanation:

x^6-x^3+27+9x^3  

=(x^2)^3+(-x)^3+(3)^3–3(x^2)(-x)(3)  

Now it has assumed the form of  

a^3+b^3+c^3–3abc which is factorised as  

(a+b+c)(a^2+b^2+c^2—ab-bc-ca)

⇒(x^2)^3+(-x)^3+(3)^3–3(x^2)(-x)(3)  

=(x² - x +3)(x∧4 + x² +9 + x³ +3x -3x²)

=(x² - x +3)(x∧4 +x³ - 2x² +9)

Answer 2

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