Factorize (y-z)whole cube+(y-z)whole square
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(y-z)³+y-z)²
taking (y-z)² common, we get:
(y-z)²(y-z+1) ans.
Hope my answer helps you...
Thank You!!.....for the Question!!
taking (y-z)² common, we get:
(y-z)²(y-z+1) ans.
Hope my answer helps you...
Thank You!!.....for the Question!!
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