Math, asked by Pavan1313, 8 months ago

Factorize : y² - 8y -15​

Answers

Answered by rumig0720
6

 {y}^{2} -  8y  + 15 = 0 \\  =  > {y}^{2}   - 3y - 5y + 15 = 0 \\  =  > y(y - 3) - 5(y - 3) = 0 \\  =  > (y - 5)(y - 3) = 0 \\ so \:  \\ y - 5 = 0 \:  \:  \:  \:  \:  \:  \:  \: or \:  \:  \:  \:  \:  \: y - 3 = 0 \\  =  > y = 5 \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: =  > y = 3

Answered by shaikhashfar123
5

Answer:

y2-8y-15

y2-3y+5y-15

y(y-3)+5(y-3)

(y-3)(y+5)

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