factors for 3x^2-27x+74=0
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Use quadratic formula x = [ -b +_ ✔️b^2-4ac ] /2a = 27 +_ ✔️729 -4*3*74 /6 = 27 +_ ✔️729 - 888 / 6 = 27+_✔️-159 /6 => roots are imaginary
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3 x^2 - 27 x + 74 = 0
factors of 3 * 74 = 3 * 37 * 2
roots = [ 27 +- root(27^2 - 4*3*74) ] / 2 = 13.5 +- 6.3 i
there are no real factors. they are only imaginary.
(x - 13.5 - 6.3 i) ( x - 13.5 + 6.3 i) = 0
factors of 3 * 74 = 3 * 37 * 2
roots = [ 27 +- root(27^2 - 4*3*74) ] / 2 = 13.5 +- 6.3 i
there are no real factors. they are only imaginary.
(x - 13.5 - 6.3 i) ( x - 13.5 + 6.3 i) = 0
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