Factors of 6a² are ?
Answers
Answer:
STEP
1
:
Equation at the end of step 1
((2•3a2) + a) - 12
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 6a2+a-12
The first term is, 6a2 its coefficient is 6 .
The middle term is, +a its coefficient is 1 .
The last term, "the constant", is -12
Step-1 : Multiply the coefficient of the first term by the constant 6 • -12 = -72
Step-2 : Find two factors of -72 whose sum equals the coefficient of the middle term, which is 1 .
-72 + 1 = -71
-36 + 2 = -34
-24 + 3 = -21
-18 + 4 = -14
-12 + 6 = -6
-9 + 8 = -1
-8 + 9 = 1 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and 9
6a2 - 8a + 9a - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
2a • (3a-4)
Add up the last 2 terms, pulling out common factors :
3 • (3a-4)
Step-5 : Add up the four terms of step 4 :
(2a+3) • (3a-4)
Which is the desired factorization
Answer:
6a^2
Step-by-step explanation:
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