Question

Geometry Easy Question​

Answer 1

$\mathfrak{\huge{Answer:-}}\\\bold{2 {cos}^{2} θ(1 + {tan}^{2}θ)} \\ = 2 \times {cos}^{2}θ \times {sec}^{2}θ (1 + {tan}^{2} θ = {sec}^{2}θ ) \\ = 2 \times {cos}^{2} θ \times \frac{1}{ {cos}^{2} θ} ( {sec}^{2} θ = \frac{1}{ {cos}^{2}θ } ) \\ = 2 \\ \boxed{\boxed{\large{\bold{2 {cos}^{2}θ(1 + {tan}^{2}θ) = 2 }}}}$