Math, asked by victoriarajputpda9y6, 1 year ago

factors of 8x³-27y³ are? how to solve

Answers

Answered by siddhartharao77
16

Given Equation is 8x^3 - 27y^3

It can be written as,

= > (2x)^3 - (3y)^3

It is in the form of a^3 - b^3 = (a - b)(a^2 + b^2 + ab).

= > (2x - 3y)(4x^2 + 9y^2 + 6xy)


Hope this helps!


victoriarajputpda9y6: thank you so so so much
siddhartharao77: welcome!
Answered by jossinmanoj
1

Answer:

a^3+b^3=(a+b) (a^2-ab+b^2)

replace b^3 by 27y^3

x^3+27b^3=(x-3y) (x^2-3xy+9y^2)

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