Question

Factors of (x^2/4-y^2/9)

Answer 1

Your question is quite wrong.

It should be

Factor of (x^2/4-y^2/9)=1

here's is your answer

(x^2 /4) - (y^2/9) = 1

=>(x/2)^2 - (y/3)^2 =1

=>(x/2 + y/2)(x/2 - y/2) = 1.

{using identity(a^2-b^2) = (a+b)(a-b)}

=>{(3x+2y)6} {(3x-2y)6} = 1

=>(9x^2 - 4y^2)/36 = 1

{using identity(a^2-b^2) = (a+b)(a-b)}

So we get,

(9x^2 - 4y^2) = 36

=>9x^2 - 4y^2 - 36 =0

Now, for this type of equation as there are more than in value unknown,we need to specify for which unknown value the equation need to be satisfied.

Hence there is no way to solve this equation.

Thanks