Question

factors of X^3 +( 1 /x^ 3)-2​

Answer 1

these is how you do it

Answer 2

Answer: 1/x³ , (x³- 1) and (x³ - 1)

Step-by-step explanation:

Given,

$x^3+\frac{1}{x^3}-2\\\;\\\text{Taking L.C.M.}\\\;\\=\frac{x^6+1-2x^3}{x^3}\\\;\\=\frac{x^6-2x^3+1}{x^3}\\\;\\\text{Splitting middle term}\\\;\\=\frac{x^6-x^3-x^3+1}{x^3}\\\;\\=\frac{x^3(x^3-1)-1(x^3-1)}{x^3}\\\;\\=\frac{(x^3-1)(x^3-1)}{x^3}\\\;\\=\frac{(x^3-1)^2}{x^3}$

Hence, factors are,

1/x³ , (x³- 1) and (x³ - 1)