Question

factors of x²- 14 x²-147 are​

Answer 1

Comparing with ax²+bx+c=0 we get,

a=1, b=(-14), c=(-147)

x²-14x-147=0

x²-21x+7x-147=0

x(x-21)+7(x-21) = 0

(x-21)(x+7) = 0

Hence, x=21 or x=(-7)