Factors of (x2 + 3x + 5) (x2 - 3x + 5) = m2 - n2,then m and n are
A
M = (x2 + 5), n = 3x
B
M = (x2 + 5), n = x
C
M = (x2 - 5), n = 3x
D
M = (x2 - 5), n = x
Answers
Answered by
0
Answer:
Given : (x
2
+3x+5)(x
2
−3x+5)= m
2
−n
2
We know that, m
2
−n
2
=(m+n)(m−n) [Identity]
We can write above equation as,
⇒ (x
2
+3x+5)(x
2
−3x+5)=((x
2
+5)+3x)((x
2
+5)−3x)
⇒ (x
2
+3x+5)(x
2
−3x+5)=(x
2
+5)
2
−(3x)
2
Therefore, m=x
2
+5 and n=3x
Answered by
1
Given : (x
2
+3x+5)(x
2
−3x+5)= m
2
−n
2
We know that, m
2
−n
2
=(m+n)(m−n) [Identity]
We can write above equation as,
⇒ (x
2
+3x+5)(x
2
−3x+5)=((x
2
+5)+3x)((x
2
+5)−3x)
⇒ (x
2
+3x+5)(x
2
−3x+5)=(x
2
+5)
2
−(3x)
2
Therefore, m=x
2
+5 and n=3x
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