factors of x²-x-12 are
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Answer:
x^2-x-12
x^2-(4-3)x-12
x^2-4x+3x-12
x (x-4)+3 (x-4)
(x+3)(x-4)
Therefore, (x+3)(x-4)=0
Either or
x+3=0 x-4=0
x=-3 x=4
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