Math, asked by sweety3875, 6 months ago

factors of x²-x-12 are ​

Answers

Answered by ajitsarma61
1

Answer:

x^2-x-12

x^2-(4-3)x-12

x^2-4x+3x-12

x (x-4)+3 (x-4)

(x+3)(x-4)

Therefore, (x+3)(x-4)=0

Either or

x+3=0 x-4=0

x=-3 x=4

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