Question

factors of4y^2-4y + 1 is .
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Answer 1

Step-by-step explanation:

$4 {y}^{2} - 4y + 1$

$= {(2y)}^{2} - 2 \times 2y \times 1 + {(1)}^{2}$

$= {(2y - 1)}^{2}$

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