Question

factors please.

6x²-3-7x​

Answer 1

Thnkxx for question...

Solution.

6x²-3-7x

=>It will also write as ....

6x²-7x-3

6x²-9x+2x-3

3x(2x-3)+1(2x-3)

(3x+1)(2x-3)

3x+1=0 2x-3=0

3x=0-1 2x=0+3

3x=(-1) 2x=3

x=(-1)/3 x=3/2

Ans....

Hope its helps uu

Answer 2

Step-by-step explanation:

Factoring  6x2-7x-3 

The first term is,  6x2  its coefficient is  6 .

The middle term is,  -7x  its coefficient is  -7 .

The last term, "the constant", is  -3 

Step-1 : Multiply the coefficient of the first term by the constant   6 • -3 = -18 

Step-2 : Find two factors of  -18  whose sum equals the coefficient of the middle term, which is   -7 .

     -18   +   1   =   -17     -9   +   2   =   -7   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  2 

                     6x2 - 9x + 2x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

                    3x • (2x-3)

              Add up the last 2 terms, pulling out common factors :

                     1 • (2x-3)

Step-5 : Add up the four terms of step 4 :

                    (3x+1)  •  (2x-3)

             Which is the desired factorization

3x+1= 0 (or) 2x-3= 0.

3x=-1 (or) 2x = 3.

x= -1/3 or x= 3/2.