factorze
8x^4+14x^2-4
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Hey user
Here is your answer :-
8x^4 + 14x^2 - 4
= 8x^4 + 16x^2 - 2x^2 - 4
= 8x^2 ( x^2 + 2 ) - 2 ( x^4 + 2 )
= ( x^2 + 2 )( 8x^2 - 2 )
= 2( x^2 + 2 )( 4x^2 - 1 )
= 2( x^2 + 2 )[ ( 2x )^2 - ( 1 )^2 ]
= 2 ( x^2 + 2 )( 2x - 1 )( 2x + 1 )
Thank you.
Here is your answer :-
8x^4 + 14x^2 - 4
= 8x^4 + 16x^2 - 2x^2 - 4
= 8x^2 ( x^2 + 2 ) - 2 ( x^4 + 2 )
= ( x^2 + 2 )( 8x^2 - 2 )
= 2( x^2 + 2 )( 4x^2 - 1 )
= 2( x^2 + 2 )[ ( 2x )^2 - ( 1 )^2 ]
= 2 ( x^2 + 2 )( 2x - 1 )( 2x + 1 )
Thank you.
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