Physics, asked by udaysharma48, 11 months ago

failure of wave theory

Answers

Answered by Anonymous
19

Actually it doesn’t explain any of the observations.

According to the Wave Theory of Light, no matter what the frequency of the incident beam of light is, if the beam has sufficient intensity then, if the beam is incident on the metal surface then, it will be able to emit electrons from the surface of the metal over a sufficient period of time.

This was against the fact that: A threshold frequency existence.

Answered by rameshsharma37
23

According to classical wave theory,

•Intensity of a wave is the energy incident per unit area per unit time.

•Energy carried by an electromagnetic wave is proportional to the square of the amplitude of the wave.

•Classical wave theory cannotexplain the first 3 observations of photoelectric effect.

1. Existence of the threshold frequency

Since energy of the wave is dependent on the square of its amplitude, the classical wave theory predicts that if sufficiently intense light is used, the electrons would absorb enough energy to escape. There should not be any threshold frequency.

2. Almost immediate emission of photoelectrons

Based on classical wave theory, electrons require a period of time before sufficient energy is absorbed for it to escape from the metal. Accordingly, a dim light after some delay would transfer sufficient energy to the electrons for ejection, whereas a very bright light would eject electrons after a short while. However, this did not happen in photoelectric effect.

 3. The independence of kinetic energy of photoelectron on intensity and the dependence on frequency

According to classical wave theory, if light of higher intensity is used, the kinetic energy of an ejected electron can be increased. This is because the greater the intensity, the larger the energy of the light wave striking the metal surface, so electrons are ejected with greater kinetic energy. However, it cannot explain why maximum kinetic energy is dependent on the frequency and independent of intensity.

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