Question

farheen Shaik dropped a stone from the terrace of a building and it touched the ground in 2 sec . the velocity of stone just before touching the ground was 19.6 metre per second.then what will be the stones initial velocity
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Answer 1

Answer:

Explanation:

Given that,

time(t) = 2s , v = 19.6m/s , a = g = 9.8 m/s^2 , u = ?

we know that,

v = u + at      ( first equation of motion )

substituting values,

ie, 19.6 = u + 9.8 x 2

u = 19.6 - 19.6 = 0 m/s

conclusion : In a free fall the initial velocity is always zero