FAST ANSWER QUESTION ( 4 OUT OF 5)
SOLVE THE FOLLOWING SYSTEM OF LINEAR EQUATION BY SUBSTITUTION METHOD:
4x-3y-8=0
6x-y-29/3=0
Answers
Answered by
11
4x-3y = 8
or, x = (8+3y)/4
= (3/4)y+2
now, 6x-y = 29/3
or, 6[(3/4)y+2]-y = 29/3
or, 18y/4 + 12-y = 29/3
or, 18y/4-y =29/3-12
or, 18y/4 = -7/3
or, 14y/4 = -7/3
or, y = -2/3
or, x = (3/4)y+2
= 2-1/2
= 3/2
hence, x= 3/2 and y = -2/3
or, x = (8+3y)/4
= (3/4)y+2
now, 6x-y = 29/3
or, 6[(3/4)y+2]-y = 29/3
or, 18y/4 + 12-y = 29/3
or, 18y/4-y =29/3-12
or, 18y/4 = -7/3
or, 14y/4 = -7/3
or, y = -2/3
or, x = (3/4)y+2
= 2-1/2
= 3/2
hence, x= 3/2 and y = -2/3
faizaankhanpatp3bt9p:
correctos
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the answer is correct
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Your answer is also very helpful thank u
Answered by
5
4x-8=3y (3)
y=4(x-2)/3
now substituting the value of y in equation 2
6x-{(4x-8)/3}-29/3
6x-4x+8/3-29/3=0
{6x.3-4x+8-29}/3 =0
18x-4x-21 =0
14x=21
x=21/14
x=3/2
again
putting value of x in equation 3
{4(3/2)-8}/3 =y
6-8=y
y=-2
y=4(x-2)/3
now substituting the value of y in equation 2
6x-{(4x-8)/3}-29/3
6x-4x+8/3-29/3=0
{6x.3-4x+8-29}/3 =0
18x-4x-21 =0
14x=21
x=21/14
x=3/2
again
putting value of x in equation 3
{4(3/2)-8}/3 =y
6-8=y
y=-2
Your answer is very helpful to me thanks
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