Question

fast ka answer ho ga math ka We know that complement of set A is  A′=U−A Given U={a,b,c,d,e,f,g,h} (i) A={a,b,c} A′={d,e,f,g,h} (ii) B={d,e,f,g} ∴B′={a,b,c,h} (iii) C={a,c,e,g} ∴C′={b,d,f,h} (iv) D={f,g,h,a} ∴D′={b,c,d,e}​

Answer 1

Answer:

I think it's helpful to you

Step-by-step explanation:

We know that complement of set A is

A

′

=U−A

Given U={a,b,c,d,e,f,g,h}

(i) A={a,b,c}

A

′

={d,e,f,g,h}

(ii) B={d,e,f,g}

∴B

′

={a,b,c,h}

(iii) C={a,c,e,g}

∴C

′

={b,d,f,h}

(iv) D={f,g,h,a}

∴D

′

={b,c,d,e}

Answer 2

hi

good evening

mai toh ek dum mast hu

aap kaise ho?