Math, asked by mysticd, 1 year ago

fast with complete explanation

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Answers

Answered by HappiestWriter012
1
Hello!

x+y=2z
z=x+y/2

x/x-z+z/y-z

x(y-z)+z(x-z)/ (x-z)(y-z)

xy-xz+xz-z²/(x-z)(y-z)

xy-z²/(x-z)(y-z)

xy-z²/(2x-x-y/2)(2y-x-y)/2
xy-z²/(x-y/2)(y-x)/2

4(xy-z²)/xy-x²-y²+xy

4(xy-z²)/(-x²-y²+2xy)

4(xy-z²)/ -(x²+y²-2xy)

-4(xy-z²)/(x-y)²

-4[4xy- (x+y)²/4] /( x-y )²

4[(x+y)²-4xy/4]/(x-y)²

4[x-y]²/4(x-y)²

4 /4
=1

There fore the answer is 1

mysticd: Check once again
HappiestWriter012: finished
mysticd: Wrong
HappiestWriter012: where wrong
mysticd: x+y=2z
mysticd: x+y=z+z
pankaj12je: 2nd step
mysticd: x-z=z-y
mysticd: x-z=-(y-z) use it now in the given problem
Answered by pankaj12je
1
Hope this helps.............
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pankaj12je: ty:))
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