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Hello!
given a=b=c
So (a+b+c)²/a²+b²+c²
=(a+a+a)²/a²+a²+a²
=(3a)²/3a²
=9a²/3a²
=3
/*Hope helped*/
given a=b=c
So (a+b+c)²/a²+b²+c²
=(a+a+a)²/a²+a²+a²
=(3a)²/3a²
=9a²/3a²
=3
/*Hope helped*/
Answered by
1
If a=b=c ,
then, (a+b+c)² = (3a)²
and, a²+b²+c²= a²+a²+a²= 3a²
(3a)²/3a²=9a²/3a²=9/3=3.
then, (a+b+c)² = (3a)²
and, a²+b²+c²= a²+a²+a²= 3a²
(3a)²/3a²=9a²/3a²=9/3=3.
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