faster train takes three hour less than a slower trainfor a journey of 600 kilometre if the speed of the slower train is 10 kilometre per hour less than that of the fastest train find the speed of the two trains
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hope it will help...
Step-by-step explanation:
let speed of fast train = x km/hr
speed of slow train = x-10 km/hr
t= 600/x , 600/x-10
600/(x-10) - 600/x =3
on solving x=50
fast train =50 km/hr
slow train =50-10 = 40 km/hr
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