Question

.fastttttffttttttttttttttttttttttttttttttttttttt kro ji​

Answer 1

Answer:

It is given that the zeroes are 3+√2 and 3-√2.

so ...One is alpha and other one is beta

put the values of alpha beta in the general equation ..

x²–(sum of zeroes)x+(product of zeroes)

=x²–(6)x+(3²_√2²)

x²–6x+7

the required equation is x²–6x+7.

Step-by-step explanation:

thanks ..

Mark as brainliest answer..

Answer 2

$\large{\underline{\underline{\sf{\red{Answer-}}}}}$

$\large{\underline{\boxed{\sf{\purple{x^2-6x+7}}}}}$

$\large{\underline{\underline{\sf{\red{Explanation-}}}}}$

★ Given zeroes :

• $\sf{3+\sqrt2}$
• $\sf{3-\sqrt2}$

★ To find :

• Quadratic polynomial

★ Solution :

Sum of zeroes :

$\leadsto$ $\sf{3+\sqrt2}$$\sf{+3-\sqrt2}$

$\leadsto$ $\sf{3+\cancel{\sqrt2}+3-\cancel{\sqrt2}}$

$\leadsto$ $\sf{3+3}$

$\leadsto$ $\sf{6}$

Product of zeroes :

$\leadsto$ $\sf{(3+\sqrt2)}$$\sf{(3-\sqrt2)}$

By using :

• (a+b)(a-b) = a² - b²

$\leadsto$ $\sf{(3)^2-(\sqrt2)^2}$

$\leadsto$ $\sf{9-2}$

$\leadsto$ $\sf{7}$

Formula used :

Quadratic polynomial = x² - Sx + P

$\leadsto$ x² - (6)x + (7)

$\large{\underline{\boxed{\sf{\purple{x^2-6x+7}}}}}$