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_________________________
Angle ( a ) + Angle( b ) + 80° = 180°
( interior angles of ∆ )
( i ) Angle a + Angle b = 100° ------------- ( 1 )
_________________________
Angle ( c ) + Angle( d ) + 80° = 180°
( interior angles of ∆ )
( ii ) Angle c + Angle d = 100° ------------ ( 2 )
_________________________
By adding eqñ ( 1 ) and ( 2 )
a + b + c + d = 100 + 100
a + b + c + d = 200
In a parallelogram opposite angles are equal and that's why angle e = 80
By adding angle e ,
a + b + c + d + e = 280°
_________________________
Option ( C ) is correct
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